kx_guo
1d58bb8913
- 统一供应商异常统计为近3年数据口径 - 以近3年异常记录数作为合作频次代理值并明确提示 - 实现 A/B 缺陷占比与 S/A/B/C 层级判定 - 按供应商层级输出正常合作、加强巡检、驻厂及备选供应商等管理建议 - 完善风险卡片和供应商卡片的频次、层级、建议展示 - 补充供应商画像接口、测试和历史会话卡片兼容处理
67 lines
2.4 KiB
Python
67 lines
2.4 KiB
Python
from datetime import date
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from app.schemas.suppliers import SupplierListData, SupplierOption
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from app.services.suppliers import SupplierProfileService
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def test_supplier_tier_rules_follow_prd() -> None:
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assert SupplierProfileService.tier_for(0, 0, 0) == "新供应商"
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assert SupplierProfileService.tier_for(12, 0, 0) == "S级"
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assert SupplierProfileService.tier_for(40, 0, 4) == "A级"
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assert SupplierProfileService.tier_for(70, 0, 10) == "B级"
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assert SupplierProfileService.tier_for(40, 0, 16) == "B级"
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assert SupplierProfileService.tier_for(10, 1, 0) == "C级"
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assert SupplierProfileService.tier_for(121, 0, 0) == "C级"
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def test_supplier_alpha_is_capped_and_rounded() -> None:
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assert SupplierProfileService.alpha(0) == 1.0
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assert SupplierProfileService.alpha(42) == 1.13
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assert SupplierProfileService.alpha(148) == 1.44
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assert SupplierProfileService.alpha(200) == 1.5
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def test_supplier_list_exposes_default_highest_anomaly_supplier() -> None:
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result = SupplierListData(
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items=[
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SupplierOption(name="甲供应商", anomaly_count=2, tier="S级"),
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SupplierOption(name="乙供应商", anomaly_count=1, tier="S级"),
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],
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default_supplier="甲供应商",
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)
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assert result.default_supplier == result.items[0].name
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def test_supplier_category_breakdown_is_top_five_with_material_and_problem() -> None:
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rows = [
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{"product_category": "洗发水", "product_name": "洗发水", "material_type": "泵头", "anomaly_type": "漏液"},
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{"product_category": "洗发水", "product_name": "洗发水", "material_type": "泵头", "anomaly_type": "漏液"},
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{"product_category": "面霜", "product_name": "面霜", "material_type": "瓶子", "anomaly_type": "刮花"},
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]
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result = SupplierProfileService._categories(rows)
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assert result[0].category == "洗发水/洗护类"
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assert result[0].top_material == "泵头"
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assert result[0].top_problem == "漏液"
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def test_supplier_recent_records_are_limited_and_sorted() -> None:
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service = SupplierProfileService(object(), as_of=date(2026, 9, 7))
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rows = [
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{
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"id": index,
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"date": date(2026, 4, index),
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"product_name": "产品",
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"anomaly_type": str(index),
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"defect_level": "B",
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}
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for index in range(1, 13)
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]
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result = service._recent_records(rows)
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assert len(result) == 10
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assert result[0].case_id == 12
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